Answer to Question #100048 in General Chemistry for Beverlie

Question #100048

A gaseous mixture consists of 1.27 mol of helium, 0.36 mol of neon, and 1.58 mol of argon.
What is the mole fraction of helium in the mixture?

Expert's answer

W(He) = 1,27/(1,27+0,36+1,58) = 1,27/3,21 = 0,3956 or ≈ 40%

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