Question

An individual has the following genotype: AABbDdeeFfGghh. How many unique gametes can
they form?

Answer 1

Solution

An individual can form $2^n$ unique gametes, where $n$ is the number of heterozygous genes. The number of heterozygous genes is 4 (Bb, Dd, Ff, Gg), then the number of unique gametes is $2^3$, which equals 8.

**Answer**: individual can form 8 unique gametes.

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