Q.2 For the nitrogen molecule, calculate the following: i) Translation energy per molecule at 300K ii) Translation energy per mole at 300K iii) Number density at 298.2K iv) Concentration at 298.2K
1
Expert's answer
2014-03-14T05:10:04-0400
KE per molecule = 3/2 kT = 3/2 * 1.38e-23 * 300 = 6.21e-21 (J) & KE per mole: 3/2 RT = 3.74 kJ In the next calculations, it is suggested that the pressure is equal to the standard pressure. Let's suggest that the volume of the gas at 298.2 K is 1 m3. At 273.2 K the gas would have a volume of 1*273.2/298.2 = 0.916 m3 which is 40.9 moles = 2.46e25 molecules. So, The ND is 2.46e25 molecules / m3 at 298.2K The concentration is 40.9 moles / m3
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment