if 10.0g of AI and 5.00g of HCI are initially present,find the:
a.)limiting reactant
b.)excess reactant
c.)mass of excess reactant that will be consumed in the reaction
2Al + 6HCl----------> 2AlCl3 + 3H2
a) Limiting reactant is HCl
B) Excess reactant is Al
C) Moles of Al = 10/27= 0.37037 moles
Moles of HCl= 5/36.5 = 0.13697 moles
Excess moles of Al= (0.37037-0.13697)= 0.2334 moles
Mass of excess Al= 0.2334×27 =6.3018g
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