The pH of a sample of bile is 7.9. What is the concentration of H + in nmol L -1?
126 nmol L-1
12.6 nmol L-1
0.126 nmol L-1
1.26 nmol L-1
pH = -log[H+]
7.9 = -log[H+]
log[H+]=10−7.9 M=1.26×10−8 M=0.126×10−9 M=0.126 nmol/Llog[H+] = 10^{-7.9} \;M \\ = 1.26 \times 10^{-8} \; M\\ = 0.126 \times 10^{-9} \;M \\ = 0.126 \; nmol/Llog[H+]=10−7.9M=1.26×10−8M=0.126×10−9M=0.126nmol/L
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