What is the pH of a mixture of 5 ml of 0.1 mol/litre sodium acetate and 4 ml of 0.1 mol/litre acetic acid? (pKa of acetic acid at 25oC = 4.76)
pKa=4.76
Ka=1.74*10-5
Ka=[H+][CH3COO−]CH3COOH]Ka = \frac {[H^+] [CH_3COO^-]} {CH_3COOH]}Ka=CH3COOH][H+][CH3COO−]
[H+]=1.74×10−5×0.00050.0004=2.175×10−5[H^+] = \frac {1.74 × 10^ {-5} × 0.0005}{0.0004} = 2.175 × 10^ {-5}[H+]=0.00041.74×10−5×0.0005=2.175×10−5
pH=−log10(2.175×10−5)=4.66pH=-log_{10}(2.175×10^{-5})=4.66pH=−log10(2.175×10−5)=4.66
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