How much energy, in the form of ATP, is obtained from b-oxidation of 1 mol of linoleic acid?
answer:
Molecular Structure of linoleic acid:
Number of FADH2 = (n/2) - 1 - 2 double bonds
= (18/2) -1 -2
= 9 -3
= 6
"\\because" 8NADH + 6FADH2 + 9Acetyl CoA
No. of ATP = 8(2.5) + 6 (1.5) + 9(10)
= (20 + 9 + 90)ATP
= 119ATP
"\\therefore" Beta-oxidation of 1 mol of linoleic acid yields 119ATP
Comments
Leave a comment