Question

Calculate the amount of fructose 6 phosphate formed from glucose 6 phosphate in a 10 milliliter incubation system if 0.5M G6P is incubated overnite at 25oC and the equilibrium constant is 0.67.

Answer 1

Reaction:
Glucose-6-P& ----> Fructose-6-P
0,5 M& & 0
x& x
0,5 - x& x

For the following reaction expression of the equilibrium constant is:

K=0.67=& x/(0.5-x)
X = 0.2
n (Fructose-6-P) = 0.2 M * 0.01 L = 2 mmol