Question

What Is The Absolute Difference In [H+] Between 2 Aqueous Solutions, One Of PH 2.0 And One Of PH 3.0? What is the [OH-] concentration of the solution of pH 2.0?

Answer 1

As we know that,

$$\boxed{ P^H=-log[H^+]}$$

Therefore,

as given P^H=2 and P^H=3

$2=-log[H^+]\\10^{-2}=[H^+]$ ...ans

and

$3=-log[H^+]\\10^{-3}=[H^+]$ .......ans

So absolute difference between 1 and 2 is

$\boxed{10^{-2}-10^{-3}=0.009}$

Further for concentration of [OH^-] of P^H= 2

We know that,

$\boxed{[OH-][H+]=10^{-14}}$

so from this ,

[OH^-][10^-2]=10^-14

[OH^-]=10^-12 ,....answer