Question #132414
at 20C a cell with a pressure potential of 3 bars is in equilibrium with the surrounding .4M solution of sucrose in an open beaker. what is the molar concentration of sucrose in the cell?
1
Expert's answer
2020-09-16T07:45:26-0400

 The solute potential ΨS=iCRT\Psi_S = -iCRT , where i is the ionization constant, C is the molar concentration, R is the pressure constant (R = 0.0831 liter bars/mole K).

i = 1 (for sucrose)

ΨS(surround.)=(1)×(0.4)×(0.0831)×(273+20)\Psi_{S(surround.)} = -(1)\times (0.4)\times (0.0831)\times (273+20)

ΨS(surround.)=9.74\Psi_{S(surround.)} = -9.74

ΨS(surround.)=ΨP+ΨS\Psi_{S(surround.)} = \Psi_P + \Psi_S

9.74=3+ΨS-9.74 = 3 + \Psi_S

ΨS=12.74\Psi_S = -12.74

ΨS=iCRT\Psi_S = iCRT

12.74=(1)×C×(0.0831)×(273+20)-12.74 = -(1)\times C\times (0.0831)\times (273+20)

12.74=24.34C-12.74 = -24.34C

C=0.52  MC = 0.52\; M

Answer: 0.52 M

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