Question #132414

at 20C a cell with a pressure potential of 3 bars is in equilibrium with the surrounding .4M solution of sucrose in an open beaker. what is the molar concentration of sucrose in the cell?

Expert's answer

 The solute potential ΨS=iCRT\Psi_S = -iCRT , where i is the ionization constant, C is the molar concentration, R is the pressure constant (R = 0.0831 liter bars/mole K).

i = 1 (for sucrose)

ΨS(surround.)=(1)×(0.4)×(0.0831)×(273+20)\Psi_{S(surround.)} = -(1)\times (0.4)\times (0.0831)\times (273+20)

ΨS(surround.)=9.74\Psi_{S(surround.)} = -9.74

ΨS(surround.)=ΨP+ΨS\Psi_{S(surround.)} = \Psi_P + \Psi_S

9.74=3+ΨS-9.74 = 3 + \Psi_S

ΨS=12.74\Psi_S = -12.74

ΨS=iCRT\Psi_S = iCRT

12.74=(1)×C×(0.0831)×(273+20)-12.74 = -(1)\times C\times (0.0831)\times (273+20)

12.74=24.34C-12.74 = -24.34C

C=0.52  MC = 0.52\; M

Answer: 0.52 M

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS