Answer to Question #301514 in Physics for Stephany

Question #301514

A ball is thrown with an initial velocity of 36 m/s at 33°.



What is the initial velocity of the ball at x ang y-dimension?


What is the final velocity of the ball at x and y- dimension?


What is the time of the ball as it reaches its peak?


What is the maximum height reached of the ball?


What is the total time travel of the ball?

1
Expert's answer
2022-02-23T08:31:01-0500

Given:

v0=36  m/sv_0=36\;\rm m/s

θ=33\theta=33^\circ

What is the initial velocity of the ball at x ang y-dimension?

v0x=v0cosθ=30.2m/sv0y=v0sinθ=19.6m/sv_{0x}=v_0\cos\theta=30.2\:{\rm m/s}\\ v_{0y}=v_0\sin\theta=19.6\:\rm m/s

What is the final velocity of the ball at x and y- dimension?

vfx=v0x=30.2m/svfy=v0y=19.6m/sv_{fx}=v_{0x}=30.2\:{\rm m/s}\\ v_{fy}=-v_{0y}=-19.6\:\rm m/s

What is the time of the ball as it reaches its peak?

t=v0yg=19.69.8=2.0st=\frac{v_{0y}}{g}=\frac{19.6}{9.8}=2.0\: \rm s

What is the maximum height reached of the ball?

hmax=v0y22g=19.6mh_{\max}=\frac{v_{0y}^2}{2g}=19.6\:\rm m

What is the total time travel of the ball?

ttot=22.0s=4.0st_{tot}=2*2.0\: \rm s=4.0\: s


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