A conducting cylinder of radius 3.25 cm and length 5.6 cm has a total charge of 5.5 x 10^-9 C distributed uniformly on its surface area. Find for the potential at its surface.
The potential of electric field
"V=-\\frac{\\lambda}{2\\pi\\epsilon_0}\\ln r=-\\frac{Q}{2\\pi\\epsilon_0*\\pi r^2l}\\ln r\\\\\n=-\\frac{5.5*10^{-9}}{2\\pi*8.85*10^{-12}*\\pi (0.0325)^2*0.056}\\ln 0.0325\\\\\n=3.5*10^6\\:\\rm V"
Comments
Leave a comment