Answer to Question #288112 in Physics for Kev

Question

Jane is walking at such speed o that her kinetic energy is 20 J. What is her speed? It started to rain. Jane runs at a rate of 4.2 m/s. Find the change in her kinetic energy. Jane has a mass of 50 kg.

Answer 1

The kinetic energy is given as follows:

$$K_1 = \dfrac{mv_1^2}{2}$$

Thus, the speed is:

$$v_1 = \sqrt{\dfrac{2K_1}{m}}=\sqrt{\dfrac{2\cdot 20J}{50kg}} \approx 0.89m/s$$

In the second case:

$$K_2 = \dfrac{mv^2_2}{2} = \dfrac{50\cdot 4.2^2}{2} = 441J$$

Thus, the change in kinetic energy is:

$$K_2-K_1 = 441J-20J = 421J$$

Answer. 0.89m/s, 421J.