Answer to Question #288078 in Physics for Tunde

Question

A brass rod is 2m long at a certain temperature . what is it's lenght for a temperature rise of 100k if the expression vity of brass is 1.8*10^_6 k^7

Answer 1

Given:

$l_0=\rm 2\: m$

$\Delta T=\rm 100\: K$

$\alpha=\rm 18.8*10^{-6}\: K^{-1}$

The equation of linear temperature expansion of a length is given by

$l=l_0(1+\alpha\Delta T)$

So, the new length

$l=\rm 2\: m*(1+18.8*10^{-6}*100)=2.0038\: m$