Gas is confined in a tank at a pressure of 11.0 atm and a temperature of 25.0°C. If two-thirds of the gas is withdrawn and the temperature is raised to 75.0°C, what is the pressure of the gas remaining in the tank?
Solution
the pressure of the gas remaining in the tank is given by
"P'=\\frac{T'VP}{TV'}\\\\=\\frac{75*V*11}{25*V\/3}\\\\=99atm"
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