An electrostatic force of 20N is exerted on a charge of 8.0 x 10 3 C at point P in
an electric field. What is the magnitude of the electric field intensity at point P?
The intensity E of the electric field is "E = \\dfrac{F}{q}" , so it's a force per unit charge.
"E = \\dfrac{20\\,\\mathrm{N}}{8.0\\cdot10^3\\,\\mathrm{C}} = 0.0025\\,\\mathrm{N\/C \\;\\; (or \\;\\;V\/m)}."
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