Question #308923

In order to get his car out of the mud, a man ties one end of a rope to the front bumper and

the other end to a tree 15 m away, as shown below. He then pulls on the center of the rope

with a force of 400 N, which causes its center to be displaced 0.30 m, as shown. What is the

force of the rope on the car?


Expert's answer

Answer

The magnitude of the force on the car from the rope is

T=F2sinθθ=tan−1(F2T)θ=tan−1(0.307.5)θ=2.29°T=\frac{F}{2sin\theta}\\\theta=tan^{-1}(\frac{F}{2T}) \\\theta=tan^{-1}(\frac{0.30}{7.5})\\\theta=2.29°

Now

So tension is

T=4002sin2.29°=5005.33NT=\frac{400}{2sin2.29°}\\=5005.33N





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