Answer to Question #304228 in Electricity and Magnetism for Sim

Question #304228

A spherical conductor of radius 8 cm has a uniform surface charge density of 0.1 nC/m^2. Determine the electric field: a) on the surface of the conductor; b) at a distance of 10 cm from the centre of the conductor.


1
Expert's answer
2022-03-01T11:12:11-0500

The electric field: a) on the surface of the conductor

E=q4πϵ0r2=σϵ0E=\frac{q}{4\pi\epsilon_0r^2}=\frac{\sigma}{\epsilon_0}

E1=0.11098.851012=11V/mE_1=\frac{0.1*10^{-9}}{8.85*10^{-12}}=11\:\rm V/m

b) at a distance of 10 cm from the centre of the conductor


E2=E1r12r22=1182102=7.2V/mE_2=E_1\frac{r_1^2}{r_2^2}=11*\frac{8^2}{10^2}=7.2\:\rm V/m


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