A point charge has a charge of 8.00 x 10-11 C. At what distance from the point charge is the electrical potential (a) 12.0 V? (b) 24.0 V?
Answer.
Distance is given
"r=\\frac{kQ}{V}"
a) the distance
"r=\\frac{9*10^9*8*10^{-11}}{12}\\\\=6cm"
b) the potential
"r=\\frac{9*10^9*8*10^{-11}}{24}\\\\=3cm"
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