It is desired to have a current of 20 A in a 5- resistor when it is connected to an 80-V battery. Is there any way in which an auxiliary resistor can be connected in the circuit to increase the current in the 5- resistor to this valur? If so, what should ist resistance be?
Assume x ohm resistor connected in parallel combination
"\\frac{1}{R_{eq}}=\\frac{1}{R_1}+\\frac{1}{R_2}"
"R_{eq}=\\frac{R_1R_2}{R_1+R_2}"
"R_{eq}=\\frac{5X}{5+X}"
"V=IR_{eq}"
Put value
"80=20\\times\\frac{5X}{5+X}"
"20+4X=5X"
"X=20\\Omega"
X=20 "\\Omega" connected in parallel combination of 5"\\Omega"
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