Answer to Question #259373 in Electricity and Magnetism for ops

Question #259373

If you have available several 2.0-uF capacitors, each capable of withstanding 200V without breakdown, how would you assemble a combination having an equivalent capacitance of (a) 0.40 uF or of (b) 1.2 uF, each capable of withstanding 1000 V?


1
Expert's answer
2021-11-01T17:13:42-0400

Now use 5 capacitor in series combination

1c=12+12+12+12+12=52\frac{1}{c}=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}=\frac{5}{2}

C=25=0.4μFC=\frac{2}{5}=0.4\mu F

Now above this series line make these three line in parallel combination

Cnet=c1+c2+c3C_{net}=c_1+c_2+c_3

cnet=0.4+0.4+0.4=1.2μFc_{net}=0.4+0.4+0.4=1.2\mu F


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment