The net force on the third charge is obtained from the forces between each couple of charges:
F1=kq1q3/r2=kq1q3/((−0.6)2+0.82),F1=2.2⋅1011.F2=kq2q3/r2=kq1q3/(0.62+0.82),F2=2.2⋅1011. The angle between the forces is
θ=180°−2tan−10.80.6=106°. The magnitude of the resultant is
FR=F12+F22−2F1F2cosθ=3.1⋅1010. It is oriented in +j direction.
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