Answer to Question #254338 in Electricity and Magnetism for Vikbah

Question #254338
Three charges q1=5, q2=4 and q3=3 are located at 0.6i, 0.3i, +0.8j respectively. Find the net force exerted on q due to the charges q2 and q3
1
Expert's answer
2021-10-21T21:41:01-0400

F21=kq1q2r3rF_{21}=\frac{kq_1q_2}{r^3}r

F21=9×109×5×40.33(0.3i^)F_{21}=\frac{9\times10^9\times5\times4}{0.3^3}(-0.3\hat{i})

F21=2×1012i^NF_{21}=-2\times10^{12}\hat{i}N

F31=kq1q3r3rF_{31}=\frac{kq_1q_3}{r^3}r

F21=9×109×5×313(0.6i^+0.8j^)F_{21}=\frac{9\times10^9\times5\times3}{1^3}(-0.6\hat{i}+0.8\hat{j})

F21=1.8×1011(0.6i^+0.8j^)NF_{21}=1.8\times10^{11}(-0.6\hat{i}+0.8\hat{j})N


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