Bi=Bj+Bk=μμ02π(Ijlj+Iklk),B_i=B_j+B_k=\frac{\mu\mu_0}{2\pi}(\frac{I_j}{l_j}+\frac{I_k}{l_k}),Bi=Bj+Bk=2πμμ0(ljIj+lkIk),
BLBR=I1l+I22lI2l+I12l=2I1+I22I2+I1=57.\frac{B_L}{B_R}=\frac{\frac{I_1}{l}+\frac{I_2}{2l}}{\frac{I_2}{l}+\frac{I_1}{2l}}=\frac{2I_1+I_2}{2I_2+I_1}=\frac 57.BRBL=lI2+2lI1lI1+2lI2=2I2+I12I1+I2=75.
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