A sphere has an excess of 2,88 x 1013 electrons. What is the charge on the sphere?
Since we know that 1 electron has a charge equal to -1.602 X 10-19 C, we use the conversion factor and find the total charge of the electron excess:
"2.88\\times 10^{13}\\,{electrons}(\\dfrac{-1.602\\times10^{-19}\\,C}{1\\,{electron}})\n \\implies 2.88\\times 10^{13}\\,{electrons}=-4.614\\times10^{-6}\\,C"
In conclusion, 2.88 X 1013 electrons (the excess on the sphere) have a charge equal to -4.614 X 10-6 C.
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