Answer to Question #205796 in Electricity and Magnetism for Muhammad

Question

If a house is supplied with 120 V, 100 A service, 2400 W electric range 1000 W steam iron Ten 25W bulbs one 500W Refrigrator If all the appliances are used for 4 Hour 15 Minutes how much energy is converted in kWh? 

Answer 1

Total power = Power used by all appliances.

$Power = 2400W +1000W+10(25W)+500W$

$Power =4150 W$

$Power =4.15kW$

Therefore, $W= Power(kW)*Time(h)$

$W=Pt$

$W=(4.15kW)(4.25h)$

$W=17.6375 kWh$