Answer to Question #205728 in Electricity and Magnetism for Brandon Dalton

Question

https://lh5.googleusercontent.com/Sh5cNe3GkcFZjM-vC_mi8xpwniPAB_Q3yeeY4aIMIMMZ1jEmyp8wjdCSb6MeC1bMXEztEAEpsoi6Su7SZo01p-YJWXRZ59KXl1_Ic8xmaRMIqWCzRSeEHt_JIs6ClhI7Kw=w740

Answer 1

Gives

Velocity (c)=$2\times10^{5}m/sec$

Radius (r)=1 cm =$1\times10^{-2}m$

We know that partical motion in circuler

$\frac{mv^2}{r}=qvB$

$B=\frac{mv}{qr}$

Put value

$$B=\frac{1.67\times10^{-27}\times2\times10^5}{1.6\times10^{-19}\times10^{-2}}=2.1\times10^{-1}T$$

Option (D) is correct option