Question #175467

Three charges were present inside the wire. Charge #1 has 3.2c, charge #2 has 4.1c, and charge #3 has -2.9c. Each charge has a distance of 8m to each other.


a. What is the total force between charges #1 and #2?

b. What is the total force between charges #2 and #3?

c. What is the total force and direction of the charges assuming that our charge #1 is the starting point? 


1
Expert's answer
2021-03-26T11:27:52-0400

Answer

Force between two charged particle

F=kqqr2F=\frac{kqq'}{r^2}

a. Force between first and second charge

F12=9×109×3.2×4.1(8)2=1.8×109NF_{12}=\frac{9\times10^9\times3.2\times4.1}{(8)^2}=1.8\times10^9N

b. Force between second and third charge

F23=9×109×2.9×4.1(8)2=1.67×109NF_{23}=\frac{9\times10^9\times2.9\times4.1}{(8)^2}=1.67\times10^9N

Now

c. Force between first and third charge

F13=9×109×3.2×2.9(16)2=0.33×109NF_{13}=\frac{9\times10^9\times3.2\times2.9}{(16)^2}=0.33\times10^9N

So net force on first charge

F1=F12+F13F_{1}=F_{12}+F_{13}

=1.8×109(i)+0.33×109(i)=1.8\times10^9(-i) +0.33\times10^9(i)

=1.47×109(i)=-1.47\times10^9(i) N

In neagtive X-axis.





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