Answer to Question #301972 in Electric Circuits for Diablo

Question #301972

A proton with a speed of 2.0x10^5m/s enters a region of space in which source charges have created an electric field potential "v"; What is the proton speed after it move through a potential difference of 100volts.

- What will be the final speed if the proton replace an electron.

Mass of Proton = 1.67x10^-27kg

Mass of Electron = 9.1x10^-30kg


1
Expert's answer
2022-02-28T11:52:11-0500

Given:

vi=2.0105m/sv_i=2.0*10^5\:\rm m/s

V=100VV=100\:\rm V


The energy-work theorem says

mv222mv122=eV\frac{mv_2^2}{2}-\frac{mv_1^2}{2}=eV

v2=v12+2eV/mv_2=\sqrt{v_1^2+2eV/m}

v2=(2.0105)2+21.610191001.671027v_2=\sqrt{(2.0*10^5)^2+\frac{2*1.6*10^{-19}*100}{1.67*10^{-27}}}

v2=2.43105m/sv_2=2.43*10^5\:\rm m/s


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