Find the three current I1, I2, I3 with Kirchoff rule where R1= 100ohms, R2= 10ohms, R3= 5ohms and E1= 12volts, E2= 6volts
Answer
Using ohm's law
Curents
"I_1=\\frac{E_1}{R_1}=\\frac{12}{100}=0.12A"
"I_2=\\frac{E_2}{R_2}=\\frac{6}{10}=0.6A"
So
"I_3=I_1+I_2=0.12+0.6=0.18A"
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