Find the three current I1, I2, I3 with Kirchoff rule where R1= 100ohms, R2= 10ohms, R3= 5ohms and E1= 12volts, E2= 6volts
Answer
Using ohm's law
Curents
I1=E1R1=12100=0.12AI_1=\frac{E_1}{R_1}=\frac{12}{100}=0.12AI1=R1E1=10012=0.12A
I2=E2R2=610=0.6AI_2=\frac{E_2}{R_2}=\frac{6}{10}=0.6AI2=R2E2=106=0.6A
So
I3=I1+I2=0.12+0.6=0.18AI_3=I_1+I_2=0.12+0.6=0.18AI3=I1+I2=0.12+0.6=0.18A
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