Answer to Question #235487 in Electric Circuits for Ahmad

Question #235487
50 billion million deficit of electrons will have a charge of
1
Expert's answer
2021-09-14T09:37:14-0400

First we confirm how many electrons were removed:


N=50 billion million electronsN=(50)(109)(106) electronsN=5×1016 electronsN=\text{50 billion million electrons} \\N=(50)(10^9)(10^6)\text{ electrons} \\N=5\times10^{16}\text{ electrons}


Since we are removing electrons (because this is a deficit), the total charge will be positive:


Q=5×1016electrons×1.609×1019C1electron Q=8.045×103C=8.045mCQ=5\times10^{16}\,\cancel {\text{electrons}}\times\dfrac{1.609\times10^{-19}\,C}{1\,\cancel {electron}} \\ \text{ } \\Q=8.045\times10^{-3}\,C=8.045\,mC


In conclusion, 50 billion million deficit of electrons will have a charge of 8.045 X 10-3 C or 8.045 mC.


Reference:

  • Sears, F. W., & Zemansky, M. W. (1973). University physics.

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