how many electrons passes through a 20 ohm resistor through 10 mins if there is a drop of 30 volts a cross it
From Ohm’s Law
"V=IR \\\\\n\nI=\\frac{V}{R}= \\frac{30 \\;V}{20} = 1.5 \\;A \\\\\n\nI= \\frac{Q}{t} \\\\\n\nQ=It = (1.5 \\;A) \\times (10 \\times 60 \\;s) = 900 \\;C \\\\\n\nQ=ne \\\\\n\nn= \\frac{Q}{e} = \\frac{900 \\;C}{1.6 \\times 10^{-19} \\;C}=562.5 \\times 10^{19}"
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