i. First, from the equation for the voltage we determine:
"V_{(t)}=150sin(\\omega t)=V_{max}sin(\\omega t)=V_{max}sin(200\\pi t)"
"V_{max}=150\\,V=\\frac{\\pi}{2}V_{average}=\\sqrt{2}V_{RMS}"
"\\implies V_{average} = \\dfrac{2}{\\pi}V_{max}=\\frac{2}{\\pi}(150\\,V)=95.493\\,V" .
ii. Then, from what we stated before:
"V_{RMS}=\\frac{1}{\\sqrt{2}}V_{max}=\\frac{150\\,V}{\\sqrt{2}}=106.066\\,V" .
iii. The period can be found with the frequency: "\\omega=2\\pi f=\\dfrac{2\\pi}{T}"
"\\implies T=\\cfrac{1}{f}=\\cfrac{1}{100\\,Hz}=0.01 \\,s" .
In conclusion, we found that the DC value is Vaverage=95.493 V, while the RMS value for the voltage is VRMS=106.066 V and the period of the voltage signal T = 0.01 s.
Reference:
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