Let k ≥ 0 and f : M → M a k-Lipschitz function. Let ε > 0. Give the largest
number φ > 0, if any, such that ∀x, y ∈ M, d(x, y) < φ implies d(f(x), d(y)) < ε.
Let f : A → R, A ⊂ Rn, be an L-Lipschitz function. Then there exists an L-Lipschitz function F : Rn → R such that F|A = f.
Proof. Because the functions
"f_a (x) := f(a) + L|x - a| , a \u2208 A" ,
are L-Lipschitz on Rn, the function
"F(x) :=\\infin_{ a\u2208A} f_a (x) , F : R^n \u2192 R ,"
is L-Lipschitz by Lemma 2.1. It is obvious that F(a) = f(a) whenever a ∈ A.
The extension F in Theorem 2.3 is the largest L-Lipschitz extension of f in the sense that if G : Rn → R is L-Lipschitz and G|A = f, then G ≤ F. One can also find the smallest L-Lipschitz extension of f, by setting
"F(x) := sup_{\n\na\u2208A}\n\nf(a) - L|x - a| , x \u2208 R"
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