Question #196746

a differentiable real valued function f has at the point (1, 2), directional derivatives +2 in the direction toward (2, 2) and -2 in the direction toward (1, 1). determine the gradient vector at (1, 2) and compute the directional derivative in the direction toward (4, 6).


Expert's answer

We know that directional derivative


Duf=D.D=f.uD_uf=D.D= \nabla f.\vec{u}

     = (fxi+fyj).u(f_x i+f_y j).\vec{u}


Now directional derivative in the direction towards (2,2) is +2


i.e. (fxi+fyj)((21)i+(22)j)=2f_x i+f_y j)((2-1)i+(2-2)j)=2


(fxi+fyj).(i+0j)=2(f_xi+f_yj).(i+0j)=2 f


fx=2\Rightarrow f_x=2


Also Directional derivative towards (1,1)-


(fxi+fyj)((11)i+(12)j)=2(f_xi+f_yj)((1-1)i+(1-2)j)=-2

(fxi+fyj)(0ij)=2(f_xi+f_yj)(0i-j)=-2


fy=2-f_y=-2

fy=2\Rightarrow f_y=2


Gradient Δf=fxi+fyj\Delta f=f_x i+f_yj

           =2i+2j=2i+2j


Directional Derivative towards (4,6) is-

     =(2i+2j)((41)i+(62)j)=(2i+2j)(3i+4j)=66+8=14=(2i+2j)((4-1)i+(6-2)j)\\=(2i+2j)(3i+4j) \\ =66+8=14

    


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