Question #190651

An integrable function can have finitely many points of discontinuties. True or false with full explanation


Expert's answer

Let [a,a1],[a2,a3],.....,[an,b][a,a_1],[a_2,a_3],.....,[a_n,b] are the intervals of continuity of the function and a1,a2,.......,ana_1,a_2,.......,a_n are the points of discontinuities .

We know that continuous functions are integrable and the integral is additive in nature, so the following formula holds:

∫abf=∫aa1f+∫aa2f+...........∫anbf\int_{a}^{b}f = \int_{a}^{a_1}f+ \int_{a}^{a_2}f+...........\int_{a_n}^{b}f


If f is an integrable function, then all integrals exist, so the given problem statement is TRUE.



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