Question #188120

Check, whether the collection of G, given by

G'= { ] 1/n+1,1/n [ : n∈N } is a open curve of ]0,1[


Expert's answer

G=(5−n,5+1n)∣n∈NG={(5-n,5+\dfrac{1}{n})|n\in N}


Let Bn=(5−n,5+1n)B_n=(5-n,5+\dfrac{1}{n})


Then,B1=(4,6),B2=(3,5+12)B_1=(4,6) ,B_2=(3,5+\dfrac{1}{2})

   B3=(2,5+13),B4=(1,5+14)B_3=(2,5+\dfrac{1}{3}), B_4=(1,5+\dfrac{1}{4})

   B5=(0,5+15),.....B_5=(0,5+\dfrac{1}{5}),.....


Here B2B1,B3B2,....,Bn+1BnB_2 B_1,B_3 B_2,...., B_{n+1} B_n

Hence the collections of sets {BnB_n } is notnested.


Also, we see that, {BnB_n } are not mutually disjoint aB1∪B2≠ϕ,B2∩B3≠ϕ,...,Bn∩Bn+1≠ϕB_1 \cup B_2\neq \phi, B_2\cap B_3\neq \phi,..., B_n\cap B_{n+1}\neq \phi


Hence The given set G is not an open curve on [0,1]


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