Solve the differential equation of the following exact differential equation. Show complete solution.
(3x2y - 6x)dx + (x3 + 2y)dy = 0
"\\displaystyle\n\\text{Let $M(x,y) = 3x^2y-6x$ }\\\\\n\\int (3x^2y-6x)dx = x^3y-3x^2+h(y)\\\\\n\\text{Differentiating and comparing to $N(x,y) = x^3+2y$, we have that}\\\\\nh'(y) =2y \\implies h(y) = y^2\\\\\n\\text{Hence the solution to the given exact equation is}\\\\\nx^3y-3x^2+y^2=C"
Comments
Leave a comment