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Could you explain what „yield to maturity“ of a bond measures? How could we „read it“ as a measure of risk?

1. An organic compound is known to be nonvolatile and non-electrolyte. A 0.35- g sample is dissolved in water and diluted to 150mL. The osmotic pressure is measured as 0.04 atm at 25ºC. The approximate mass number for this compound is 1400g/mol. From the data provided in this problem and knowing that the density of the solution is 1.00g/mL


a. Calculate the freezing point of the solutions

b. Determine if the freezing point change would be a good way to determine the molecular mass of the compound

c. Would the boiling point change be a better determining factor than the freezing point change?


Salt is often used to melt ice and snow on roads in the winter and the temperature right now is -4.500ºC. How much NaCl (complete dissociation) would be necessary to melt 1000kg of ice by bringing down the freezing temperature to - 4.500ºC?


A solution was produced by dissolving 3.75 g of a nonvolatile solute in 95g of acetone. The boiling point of pure acetone was observed to be 55.95 ºC, while the boiling point of the solution was 56.50ºC. If the boiling point for acetone is 1.71ºC/m, what is the approximate molar mass of solute?


Step 1: First compute the molality of the boiling point equation.

Step 2. Then, from the definition of molality, compute the number of moles solute, n(solute), in the sample.

Step 3. Solve for the molar mass. 


A solution containing 4.50 g of a non-electrolyte (i=1) dissolved in 125 g of water freezes at -0.372ºC. Calculate the molar mass of the solute.


Step 1: First compute the molality of the freezing point equation.

Step 2. Then, from the definition of molality, compute the number of moles solute, n(solute), in the sample.

Step 3. Solve for the molar mass


Write a program to increment N by 5, if N me s greater than 10, otherwise by 1.

Write an essay on the topic “When are colligative properties considered beneficial to life?”

Using inheritance, one class can acquire the properties of others. Consider the  following Animal class: 

class Animal{ 

 void walk(){ 

 System.out.println("I am walking"); 

 } 

This class has only one method, walk. Next, we want to create a Bird class that also  has a fly method. We do this using extends keyword: 

class Bird extends Animal { 

 void fly() { 

 System.out.println("I am flying"); 

 } 

Finally, we can create a Bird object that can both fly and walk

public class Solution{ 

 public static void main(String[] args){ 


 Bird bird = new Bird(); 

 bird.walk(); 

 bird.fly(); 

 } 

The above code will print: 

I am walking 

I am flying 

This means that a Bird object has all the properties that an Animal object has, as well  as some additional unique properties. 

The code above is provided for you in your editor. You must add a sing method to  the Bird class, then modify the main method accordingly so that the code prints the  following lines: 

I am walking 

I am flying

I am singing


Using inheritance, one class can acquire the properties of others. Consider the  following Animal class: 

class Animal{ 

 void walk(){ 

 System.out.println("I am walking"); 

 } 

This class has only one method, walk. Next, we want to create a Bird class that also  has a fly method. We do this using extends keyword: 

class Bird extends Animal { 

 void fly() { 

 System.out.println("I am flying"); 

 } 

Finally, we can create a Bird object that can both fly and walk

public class Solution{ 

 public static void main(String[] args){ 


 Bird bird = new Bird(); 

 bird.walk(); 

 bird.fly(); 

 } 

The above code will print: 

I am walking 

I am flying 

This means that a Bird object has all the properties that an Animal object has, as well  as some additional unique properties. 

The code above is provided for you in your editor. You must add a sing method to  the Bird class, then modify the main method accordingly so that the code prints the  following lines: 

I am walking 

I am flying

I am singing


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