Question #87436
The wavefunction for a particle is defined by:
ψ(X)= [NCos(2πx/L, for –L/4≤x≤L/4
[ 0, otherwise
Determine
i) the normalization constant N, and
ii) the probability that the particle will be found between x = 0 and x = L / 8.
1
Expert's answer
2019-04-04T09:04:15-0400

i) Normalization constant could be found using:


L/4L/4ψ(x)2dx=1\int_{-L/4}^{L/4}{|\psi(x)|^2 dx}=1

This gives:

L/4L/4N2cos22πxLdx=N2L4=1\int_{-L/4}^{L/4}{N^2*\cos^2{\frac{2\pi x}{L}} dx}=N^2*\frac{L}{4}=1

N=2LN=\frac{2}{\sqrt{L}}

So, normalized wavefunction is


ψ(x)=2Lcos2πxL\psi(x)=\frac{2}{\sqrt{L}}*\cos{\frac{2\pi x}{L}}

ii) The probability to find a particle between 0 and L/8 equals:


P=0L/8ψ(x)2dx=0L/84Lcos22πxLdx=4LL(2+π)16πP=\int_{0}^{L/8}{|\psi(x)|^2 dx}=\int_{0}^{L/8}{\frac{4}{L}*\cos^2{\frac{2\pi x}{L}} dx}=\frac{4}{L}*\frac{L(2+\pi)}{16\pi}

P=(2+π)4π0.41P=\frac{(2+\pi)}{4\pi}\approx 0.41


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