Answer to Question #8710 in Quantum Mechanics for Mariam Farhat

Question

1. A photon and an electron each has a de Broglie wavelength of 5nm. Compare their energies in eV(electovolt)
b) If the proton is confined to a nucleus of radius 2*10^-14m, estimate the uncertainty in its linear momentum.


Equations:

De Broglie wavelength = h/p --> h is Planck's constant and p is the linear momentum(mass*velocity).

Also, de Broglie wavelength = h/ sqrt(2m(e)deltaV) --> m = mass , (e) is the absolute value of the charge of the electron(-1.6*10^-19) and delta V is the stopping potential.

Heisenberg's Uncertainty Principle: delta x * delta p is greater or equal to h/2pi --> x is the position, p is the linear momentum (mass * velocity) , h ( Planck's constant 6.63*10^-34 J*s )