We have nontrivial commutation relations. Then consider the following provisions. We have the scalar product of vectors A and B, that is, it will be the following expression: A·B=xAxB+yAyB+zAzB.
Let's look at the switch: [A·B, Jx]=xAxBJx-JxxAxB=0, because the product of X will be a number, and it can be rearranged in any order.
Let's look at the switch: [A·B, Jy]=yAyBJy-JyyAyB=0, because the product of Y will be a number, and it can be rearranged in any order.
Let's look at the switch: [A·B, Jz]=zAzBJz-JzzAzB=0, because the product of X will be a number, and it can be rearranged in any order.
In this way, A·B and Jx, A·B and Jy, A·B and Jz commute.
Comments
Leave a comment