A quantum particle is moving in a harmonic oscillator potential v(x)=m*omega^(2)*x^(2)/2.
The eigenstates are denoted by |n> while the wave functions are Psi n (x) = <x|n>.
At t=0, the system in the state: |Psi(t=0)>=A*sum from n of (1/sqrt(2))^2 | n >
Find the constant A, obtain the expression for the wave function Psi(x,t) = <x | Psi(t)> at a latter time, calculate the probability density |Psi(x,t)|^2 and the expectation value of the energy.
1
Expert's answer
2011-06-09T14:39:58-0400
Unfortunately, your question requires a lot of work and cannot be done for free. Submit it with all requirements as an assignment to our control panel and we'll assist you.
Comments
Leave a comment