Answer to Question #297236 in Quantum Mechanics for Sneha

Question

A body of volume 36cc floats with ¾ of its volume submerged in water. The density of body is

a) 0.25 g/cc

b) 0.75 g/cc

c) 0.9 g/cc

d) 0.1 g/cc

Answer 1

Answer

body of volume V=36cc=36*10^-6m

Submerged in water V'=27*10^-6 m

Using the buoyancy force

$F_B=W\\\rho_wV'g=\rho Vg\\$

So density of body

$\rho =\frac{\rho_w V'}{V}\\=\frac{1000*27*10^{-6}}{36 *10^{-6} }\\=0.75g/cc$