Answer to Question #286288 in Quantum Mechanics for Pheba

Question

ψ=squar 2/L sin (nPie x/2) find the value of x

Answer 1

$\psi=\sqrt{\frac 2L}\sin(\frac {n\pi x}2),$

$-\pi≤\frac{n\pi x}2≤\pi,$

$-2≤nx≤2,$

$-\frac 2n≤x≤\frac 2n,~n=1,2,3,...$