Answer to Question #283268 in Quantum Mechanics for abhi

Question

If the energy of electron in second excited state is 9eV in an infinite potential box . The ground state energy of the particle is:

Answer 1

$E_2=E_0(1-\frac 1{2^2}),\implies$

$E_0=\frac 43 E_2=\frac 43\cdot 9=12~eV.$