Given:
λ=36.5∗10−8m
I=10−8W/m2
k=0.8
ϕ=1.6eV=2.56∗10−19J
(a) the rate of production of electron from unit area is given by
AdtdN=E0kI=hckIλ
AdtdN=6.63∗10−34∗3.0∗1080.8∗10−8∗36.5∗10−8=1.47∗10101/m2⋅s(b) the absorbed energy per square meter is given by
E/At=kI=0.8∗10−8=8.0∗10−9W/m2 (c) the kinetic energy of the produced electrons is given by
Ek=hc/λ−ϕ
Ek=36.5∗10−86.63∗10−34∗3.0∗108−2.56∗10−19=2.88∗10−19J=1.8eV
Comments
Leave a comment