Answer to Question #347534 in Physics for Loie

Question

If a 4.0x10¹⁸ atoms decay with a life of 2.3 years, how many are remaining after 3.7 years?

Answer 1

$$N=N_0*2^{-t/t_{1/2}}\\ =4.0*10^{18}*2^{-3.7/2.3}=1.3*10^{18}$$