Answer to Question #347449 in Physics for Mphundu

Question #347449

A person can throw a ball at a maximum horizontal range of 120m. How high would the ball go straight up? [6 marks]

1
Expert's answer
2022-06-02T10:25:46-0400

θ=45\theta=45^\circ

R=120mR=120\:\rm m

R=v02sin2θg=v02gR=\frac{v_0^2\sin2\theta}{g}=\frac{v_0^2}{g}

hmax=v02sin2θ2g=R2sin2θh_{\max}=\frac{v_0^2\sin^2\theta}{2g}=\frac{R}{2}\sin^2\theta

hmax=120  m2sin245=30mh_{\max}=\frac{120\;\rm m}{2}\sin^245^\circ=30\:\rm m


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Comments

Mphundu
02.06.22, 18:10

Thanks a lot.. I really appreciate

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