A 50 kg tricycle travelling 6 m/s east and another tricycle with the same mass moving to the west at 3 m/s collided. Suppose the
collision did not damage any of the vehicles but caused the tricycles to move to the west at 3 m/s and to the east at 6 m/s, respectively.
Prove the law of conservation of momentum in this scenario.
Given:
"m_1=m_2=m"
"v_{1x}=6\\:\\rm m\/s"
"v_{2x}=-3\\:\\rm m\/s"
"v_{1x}'=-3\\:\\rm m\/s"
"v_{2x}'=6\\:\\rm m\/s"
The law of conservation of the momentum says
"m_1v_{1x}+m_2v_{2x}=m_1v_{1x}'+m_2v_{2x}'""m*6+m*(-3)=m*(-3)+m*6"
"3m=3m"
Thus, the momentum of the system is conserved.
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